# Ap physics multiple choice practice momentum and impulse relationship

### AP Physics 1 & 2 Practice Questions | Albert

Conservation of Linear Momentum Objective In this series of experiments, the Calculate the percent difference between the theoretical and experimental values of v f using .. AP Physics Multiple Choice Practice Momentum and Impulse 1. ANSWERS - AP Physics Multiple Choice Practice – Momentum and Impulse . F g / g with g as 10 to be used in the impulse equation. momentum and impulse, make predictions about motions of objects before . central question: How are force and impulse related to linear momentum and Science Practice is also addressed in this investigation.] patterns or relationships. . multiple times to look for patterns in the data which indicate the role mass.

Assume that the braking force is the resultant force acting on the car. State and explain how this affects the braking distance of the car. Assume that the car experiences the same braking force as in part a. From the skid marks and debris on the road the investigator knows that the collision took place at the point marked X.

The vehicles locked together on impact and vehicle A was pushed backwards a distance of 8. For the road conditions and vehicle masses the average frictional force between the road and the vehicles immediately after the collision was known to be N. Calculate the speed of vehicle B just before impact. State and explain which driver is likely to experience the higher force during the impact.

Explain how the ejection of the waste gases in one direction makes the rocket move in the opposite direction. The gas is ejected with a speed of 2.

Show that the average thrust on the rocket is about 40 MN. Total 7 marks Q The supply delivers water at a rate of 0. Calculate the force on the hose.

Explain why there is no overall effect on the rotation of the Earth. The figure below shows a neutron of mass kg about to collide inelastically with a stationary uranium nucleus of mass kg.

During the collision, the neutron will be absorbed by the uranium nucleus. Mass times velocity, kilogram meters per second. And what's the initial momentum in the y direction? Well B isn't moving at all, so it has no momentum in any direction. And A, all of A's movement is in the x direction.

### Unit 5: Collisions: - AP Physics 1 - 1

It's not moving at an angle or up at all, so it has no momentum in the y direction. So we immediately know that after the collision, the combined momentum of both of these balls in the x direction has to be 30, and the combined momentum of both of these balls in the y direction has to be 0.

So let's figure out what A's momentum in the x and y directions are. So to figure out what A's momentum is, we just have to figure out what A's velocity in the x and y directions are and then multiply that times the mass. Because mass doesn't have any direction. So let's figure out the x and y components of this velocity. Let's do the x component of the vector first. So the x is just this vector. Change colors to keep things interesting.

The y is this vector. That is the y component. And so, what are those? And this hopefully, is going to be almost second nature to you if you've been watching all of the other videos on Newton's laws. And I reassure you, this is the hardest part of any of these multi-dimensional trig problems-- Multi-dimensional physics problems, which really are just trig problems. So if we want to figure out the x component, so the velocity of A in the x direction, what is it equal to?

Well this is adjacent to the angle. We know the hypotenuse. So we know VA sub x or the velocity of A in the x direction over the hypotenuse, over 2 meters per second, is equal to what? Is equal to cosine of 30 degrees. Or the velocity of A in the x direction is equal to 2 cosine of 30 degrees. What's cosine of 30 degrees? It's square root of 3 over 2. This is square root of 3 over 2. And square root of 3 over 2 times 2 is equal to square root of 3.

So this is equal to the square root of 3 meters per second. And what is the velocity of A in the y direction? Well hopefully, this second nature to you as well. But since opposite over hypotenuse is equal to the sine of So VA in the y direction is equal to 2 times the sine of 30 degrees. So after the collision, A is moving at 1 meter per second up. One meter per second in the upwards direction.

And it's moving at square root of 3 meters per second in the rightwards direction. So what is going to be A's momentum in each of the directions? Well, we figured out its velocity, so we just multiply each of the velocities times the mass.

## AP Physics C - Momentum

So A has a mass of 10 kilograms. And this is going to be the final momentum. Momentum of A in the x direction is going to equal square root of 3 times Square root of 3 is the velocity, 10 is the mass. Place m 2 in the middle of the two photogate sensors.

### Learn AP Physics - Momentum

Then set m 1 in motion with a moderate speed. Record the speed of m 1 v 1i when it passes the first photogate and the speed of v f when they pass the second one. Flip the magnetic insert on one of the carts, so that the inserts are repelling each other instead of attracting. Students need to think about how to measure v 1f in elastic collisions.

Data Analysis Inelastic Collisions 1. Calculate the percent difference between the theoretical and experimental values of v f using the following equation for theoretical values. Plot P f as a function of P i for each case. Determine the slope of this line and record it on your data sheet.

Calculate the percent difference between the theoretical and experimental values of v 1f and v 2f. Use Equation 5 to determine the theoretical values. Plot KE f as a function of KE i for each case. Suppose the magnetic insert on the carts was replaced with velcro to hold the carts together when they collided.

What effect would the velcro have on the conservation of momentum between the two carts? Suppose the air track was tilted.